logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  AIMS  >>  Class12  >>  Chemistry
0 votes

An ionic compound made up of atoms A and B has a face-centred cubic arrangement in which atoms A are at the corners and atoms B are at the face-centres. If one of the atoms is missing from the corner, what is the simplest formula of the compound?

$\begin{array}{1 1}(A)\;A_6B_{23}&(B)\;A_7B_{27}\\(C)\;A_7B_{24}&(D)\;A_6B_{24}\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Number of atoms of A at the corners = 7 (because one A is missing)
$\therefore$ Contribution atoms of A towards unit cell=$7\times \large\frac{1}{8}=\frac{7}{8}$
Number of atoms B at face-centres = 6
$\therefore$ Contribution of atom B towards unit cell =$6\times \large\frac{1}{2}$$=3$
Ratio of A : B =$\large\frac{7}{8} $$: 3=7 : 24$
$\therefore$ Formula is $A_7B_{24}$
Hence (C) is the correct answer.
answered May 28, 2014 by sreemathi.v
 
Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...