$\begin{array}{1 1}(A)\;X_2Y&(B)\;X_3Y\\(C)\;XY&(D)\;\text{None of these}\end{array} $

It is known that the number of tetrahedral voids formed is equal to twice the number of atoms of element X.

It is given that only $\large\frac{1}{4}^{th}$ of the tetrahedral voids are occupied by the atoms of element Y.

Therefore, ratio of the number of atoms of X and Y =$ 1.2\times \large\frac{1}{4}$$=2 : 1$

Hence, the formula of the compound formed is $X_2Y$

Hence (A) is the correct answer.

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