Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS  >>  Class12  >>  Chemistry
0 votes

Atoms of element B form hcp lattice and those of the element A occupy $\large\frac{2}{3}^{rd}$ of tetrahedral voids. What is the formula of the compound formed by the elements A and B?

$\begin{array}{1 1}(A)\;A_2B_3&(B)\;A_4B_3\\(C)\;AB&(D)\;\text{None of these}\end{array} $

Can you answer this question?

1 Answer

0 votes
The number of tetrahedral voids formed is equal to twice the number of atoms of element B and only $\large\frac{2}{3}^{rd}$ of these are occupied by the atoms of element A.
Hence the ratio of the number of atoms of A and B is $2\times \large\frac{2}{3}$$ : 1$ or 4 : 3 and the formula of the compound is $A_4B_3$
Hence (B) is the correct answer.
answered May 28, 2014 by sreemathi.v
Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App