logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  AIMS  >>  Class12  >>  Chemistry
0 votes

Atoms of element B form hcp lattice and those of the element A occupy $\large\frac{2}{3}^{rd}$ of tetrahedral voids. What is the formula of the compound formed by the elements A and B?

$\begin{array}{1 1}(A)\;A_2B_3&(B)\;A_4B_3\\(C)\;AB&(D)\;\text{None of these}\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
The number of tetrahedral voids formed is equal to twice the number of atoms of element B and only $\large\frac{2}{3}^{rd}$ of these are occupied by the atoms of element A.
Hence the ratio of the number of atoms of A and B is $2\times \large\frac{2}{3}$$ : 1$ or 4 : 3 and the formula of the compound is $A_4B_3$
Hence (B) is the correct answer.
answered May 28, 2014 by sreemathi.v
 
Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...