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Atoms of element B form hcp lattice and those of the element A occupy $\large\frac{2}{3}^{rd}$ of tetrahedral voids. What is the formula of the compound formed by the elements A and B?

$\begin{array}{1 1}(A)\;A_2B_3&(B)\;A_4B_3\\(C)\;AB&(D)\;\text{None of these}\end{array} $

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The number of tetrahedral voids formed is equal to twice the number of atoms of element B and only $\large\frac{2}{3}^{rd}$ of these are occupied by the atoms of element A.
Hence the ratio of the number of atoms of A and B is $2\times \large\frac{2}{3}$$ : 1$ or 4 : 3 and the formula of the compound is $A_4B_3$
Hence (B) is the correct answer.
answered May 28, 2014 by sreemathi.v
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