$\begin{array}{1 1}(A)\;A_2B_3&(B)\;A_4B_3\\(C)\;AB&(D)\;\text{None of these}\end{array} $

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The number of tetrahedral voids formed is equal to twice the number of atoms of element B and only $\large\frac{2}{3}^{rd}$ of these are occupied by the atoms of element A.

Hence the ratio of the number of atoms of A and B is $2\times \large\frac{2}{3}$$ : 1$ or 4 : 3 and the formula of the compound is $A_4B_3$

Hence (B) is the correct answer.

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