$\begin{array}{1 1}(A)\;Q \\(B)\;-Q\\(C)\;2Q \\(D)\;0 \end{array} $

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When C and A are placed in contact, charge of A equally divides in two spheres.

Therefore charge on each A and $C = +2Q$

Now, C is placed in contact with B, then charge on each B and becomes

$\qquad=\large\frac{2Q+(-10Q0)}{2}$$=-4Q$

When A and B are placed in contact then charge on each A and B becomes

$\qquad=\large\frac{2Q+(-4Q)}{2}$$=-Q$

Hence B is the correct answer .

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