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How much positive and negative charge is there in a cup (250 g) of water?

$\begin{array}{1 1}(A)\;1.34 \times 10^7 \;c \\(B)\;1.47 \times 10^7 \;c \\(C)\;2.34 \times 10^7 \;c \\(D)\;9.34 \times 10^7 \;c \end{array} $

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Molecular mass of water $=18g$
No. of molecules in 18 g of water $= 6.02 \times 10^{23}$
No. of molecules in $250\; g$ of water $=\large\frac{250}{18} $$ \times 6.023 \times10^{23}$
One molecule of water contains two hydrogen atoms and one oxygen atom, i.e., 10 electrons and 10 protons.
Hence the total positive and total negative charge has the same magnitude.
$\qquad=\large\frac{250}{18}$$ \times 10^{29} \times 10 \times 1.602 \times 10^{-19}\;C$
$\qquad= 1.34 \times 10^7 \;C$
Hence A is the correct answer.
answered May 28, 2014 by meena.p

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