# A copper sphere of mass $2\; g$ contains nearly $2 × 10^{22} atoms$. The charge on the nucleus of each atom is $29\;e$. What fraction of the electrons must be removed from the sphere to give it a charge of $+2 \mu C$?

$\begin{array}{1 1}(A)\;2.16 \times 10^{-11}\\ (B)\;1.16 \times 10^{-11} \\(C)\;6.16 \times 10^{-11} \\(D)\; 2.16 \times 10^{-9}\end{array}$

Ratio is : $2.16 \times 10^{-11}$