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When the planet Jupiter is at a distance of 824.7 million kilometers from the Earth, its angular diameter is measured to be 35.72" of arc. Calculate the diameter of Jupiter.

$\begin {array} {1 1} (A)\;14.35 \times 10^5kg & \quad (B)\;143.5 \times 10^5kg \\ (C)\;143 \times 10^5kg & \quad (D)\;1.435 \times 10^5kg \end {array}$

$1.435 \times 10^5kg$