Ask Questions, Get Answers


A ray of light is incident from a denser to a rarer medium . The critical angle for total reflection is $\;\theta_{iC}\;$ and the Brewster's angle of incident is $\;\theta_{iB}\;$, such that $\;\large\frac{sin \theta_{iC}}{sin \theta_{iB}}=\eta= \normalsize 1.28\;$ .The relative refractive index of the two media is :


1 Answer

Ans is c = 0.8 , just use formula for brewster angle and critical angle with their expanded form as sin ic = n1/n2 and tan i = n2/n1 and solve for both considering situation for brewster angle.
answered Dec 3, 2016 by jimyjayant_1

Related questions