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A ray of light is incident from a denser to a rarer medium . The critical angle for total reflection is $\;\theta_{iC}\;$ and the Brewster's angle of incident is $\;\theta_{iB}\;$, such that $\;\large\frac{sin \theta_{iC}}{sin \theta_{iB}}=\eta= \normalsize 1.28\;$ .The relative refractive index of the two media is :

$(a)\;0.2\qquad(b)\;0.4\qquad(c)\;0.8\qquad(d)\;0.9$

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Ans is c = 0.8 , just use formula for brewster angle and critical angle with their expanded form as sin ic = n1/n2 and tan i = n2/n1 and solve for both considering situation for brewster angle.
answered Dec 3 by jimyjayant_1
 

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