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Two equal charges (q each) are placed at the vertices B and D of the square ABCD (as shown in the figure). The sides of the square are of length a.What charge should be placed at the corner C, such that the electric field at A becomes zero?

$\begin{array}{1 1}(A)\;+2q \\ (B)\;-2q \\ (C)\;-2 \sqrt {2q} \\(D)\;+2 \sqrt {2q} \end{array} $

1 Answer

$-2 \sqrt {2q}$ is correct.
Hence C is the correct answer.
answered May 29, 2014 by meena.p

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