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Evaluate : $ \int_0^{1.5} [x] \: dx $

1 Answer

Let I = int of x On integrating we get X^2/2 On applying limits we get 1.5^2/2 - 0 = 2.25/2=1.125
answered Nov 30, 2013 by vijayalakshmi_ramakrishnans
 
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