logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  AIMS  >>  Class12  >>  Physics  >>  Electric Charges and Fields
0 votes

Consider the charges q, q, and –q placed at the vertices of an equilateral triangle, as shown in Figure . What is the force on each charge?

Can you answer this question?
 
 

1 Answer

0 votes
The forces acting on charge q at A due to charges q at B and –q at C are $F_{12}$ along BA and $F_{13}$ along AC respectively, as shown in Figure .
By the parallelogram law, the total force $F_1$ on the charge q at A is given by $F_1 = F$ where is a unit vector along BC.
The force of attraction or repulsion for each pair of charges has the same magnitude $F= \large\frac{q^2}{4 \pi \in_0 j^2}$
The total force $F_2$ on charge q at B is thus F2 = F , where is a unit vector along AC.
Similarly the total force on charge $-q$ at C is $F_3=\sqrt 3 F \hat {n}$, Where $\hat n$ is the unit vector along the direction bisecting the $\angle BCA$
It is interesting to see that the sum of the forces on the three charges is zero, i.e.,
$F_1+F_2+F_3=0$
The result is not at all surprising. It follows straight from the fact that Coulomb’s law is consistent with Newton’s third law.
answered May 29, 2014 by meena.p
 
Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...