Using elementary transformations, find the inverse of the matrix if it exists - $ \begin{bmatrix} 2 & -3 & 3 \\ 2 & 2 & 3 \\ 3 & -2 & 2 \end{bmatrix} $

Question

$\begin{array}{1 1}A^{-1}=\frac{1}{5}\begin{bmatrix}-2 & 0 & 3\\-1 & 0& 0\\2 & 1 & -0\end{bmatrix} \\ \text{Does not exist} \\ A^{-1}=\frac{1}{5}\begin{bmatrix}-2 & 0 & 3\\-1 & 1& 0\\2 & 1 & -2\end{bmatrix} \\A^{-1}=\frac{1}{5}\begin{bmatrix}-9 & 0 & 3\\-1 & 0& 0\\2 & 1 & -2\end{bmatrix} \end{array} $