In the above solution, it is proved that the area of the smaller region bounded by the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1,$and the line $\frac{x}{a}+\frac{y}{b}=1$, is $\frac{ab}{4}(\pi-2)sq. units.$

In this case, given $a = 3$, $b = 2$, the area = $\large\frac{3 \times 2 }{4}$$(\pi - 2) $$\approx 1.71$ sq units.