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Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Solid State
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Iron changes its crystal structure from body-centred to cubic close-packed structure when heated to $916^{\large\circ}C$. Calculate the ratio of the density of the bcc crystal to that of ccp crystal, assuming that the metallic radius of the atom does not change.

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In the bcc packing, the space occupies is 68% of the total volume available while in ccp, the space occupied is 74%. This means that for the same volume masses of bcc and ccp are in the ratio of 68 : 74. As the volume is same, ratio of density is also same viz 68 : 74
$\large\frac{d_{bcc}}{d_{ccp}}=\frac{68}{74}=$$0.919$
Hence (B) is the correct answer.
answered May 30, 2014 by sreemathi.v
 

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