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The two ions $A^+$ and $B^-$ have radii 88 pm and 200 pm respectively. In the close packed crystal of compound AB, predict the coordination number of $A^+$.

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$\large\frac{r^+}{r^-}=\frac{88}{200}$$=0.44$
It lies in the range of 0.414 – 0.732
Hence, the coordination number of $A^+ = 6$
Hence (A) is the correct answer.
answered May 30, 2014