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Chromium metal crystallises in a body centred cubic lattice. The length of the unit cell edge is found to be 287 pm. Calculate the atomic radius of chromium.

For body centred cubic lattice, r =$\large\frac{\sqrt 3 a}{4}$
Given, edge length, a =287 pm
$r=\large\frac{\sqrt 3\times 287}{4}$
$\;\;=\large\frac{1.73\times 287}{4}$
r = 124.12 pm
Hence (A) is the correct answer.