Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS  >>  Class11  >>  Physics  >>  Units and Measurement
0 votes

The angle of elevation of a tower at a point on the ground is $24^{\circ}$. When the point is shifted 20.02 m towards the base of the tower, the angle of elevation becomes $30^{\circ}$. What is the height of the tower ? ( Take $\tan 30^{\circ} = 0.577$ and $ \tan 24^{\circ} = 0.445$ )

Can you answer this question?

1 Answer

0 votes
Ans : (C)
38.94 m
answered May 30, 2014 by thanvigandhi_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App