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Home  >>  AIMS  >>  Class11  >>  Physics  >>  Units and Measurement
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A physical quantity P is related to four observables a, b, c and d as follows: $P = \large\frac{a^3b^2}{( \sqrt{CD})}$ The percentage errors of measurement in a, b, c and d are 1%, 3%, 4% and 2%, respectively. What is the percentage error in the quantity P? If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result ?

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13% ; 3.8
Hence (D) is the correct answer
answered May 30, 2014 by thanvigandhi_1
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