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Two resistors of resistances $R_1 = 100 \pm 3\: ohm $ and $R_2 = 200 \pm 4\: ohm$ are connected in parallel. Find the equivalent resistance of the parallel combination by using $ \large\frac{1}{R'}$$= \large\frac{1}{R_1}$$+ \large\frac{1}{R_2}$ and $ \large\frac{\Delta R'}{R'^{2}}$$= \large\frac{\Delta R_1}{R_1^2}$$+ \large\frac{\Delta R_2}{R_2^2}$

1 Answer

$ 66.7 \pm 1.80$ ohm
Hence (B) is the correct answer.
answered May 30, 2014 by thanvigandhi_1
 
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