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Find the relative error in Z, if $Z = A^4B^{\Large\frac{1}{3}}CD^{\Large\frac{3}{2}}$.

1 Answer

The relative error in Z is $ \large\frac{\Delta Z}{Z}$$ = 4\bigg(\large\frac{\Delta A}{A} \bigg)$$ + \bigg( \large\frac{1}{3} \bigg)$$ \bigg( \large\frac{\Delta B}{B} \bigg) + \bigg( \large\frac{\Delta C}{C} \bigg) + \bigg( \large\frac{3}{2} \bigg)$$ \bigg (\large\frac{\Delta D}{D} \bigg).$
answered May 30, 2014 by thanvigandhi_1
 

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