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The period of oscillation of a simple pendulum is $T= 2 \pi \sqrt{\Large\frac{L}{g}}.$ L is about 10 cm and is known to 1 mm accuracy. The period of oscillation is about 0.5 second. The time of 100 oscillations is measured with a wrist watch of 1 s resolution. What is the accuracy in the determination of g?

1 Answer

Hence (D) is the correct answer.
answered Jun 1, 2014 by thanvigandhi_1