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# The period of oscillation of a simple pendulum is $T = 2 \pi \sqrt{\large\frac{L}{g}}$. Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. What is the accuracy in the determination of g?

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Hence (C) is the correct answer.
answered Jun 1, 2014

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