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Home  >>  AIMS  >>  Class11  >>  Physics  >>  Units and Measurement
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A capacitor of capacitance $3.0 \pm 0.2 \mu F$ is charged to a voltage of $40 \pm 0.1 V$. What is the amount of charge on the capacitor?

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$ (120 \pm 6.92) \times 10^{−6 } C$
Hence (D) is the correct answer.
answered Jun 1, 2014 by thanvigandhi_1

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