# Silver crystallises in fcc lattice. If the edge length of the unit cell is $4.07 × 10^{−8} cm$ and density of the crystal is 10.5 $g cm^{−3}$, calculate the atomic mass of silver. $(NA = 6.02 × 10^{23} atoms mol^{−1}$).

## 1 Answer

106.5
Hence (A) is the correct answer.
answered Jun 2, 2014