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Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Solid State
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Iron has a body centred cubic unit cell with a cell edge of 286.65 pm. The density of iron is 7.874 g $cm^{−3}$. Use this information to calculate Avogadro's number. (At. mass of iron =56 g $mol^{−1}$)

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$6.03\times 10^{23}$
Hence (A) is the correct answer.
answered Jun 2, 2014 by sreemathi.v

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