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An element ‘X' occurs in bcc structure with cell edge 290 pm. Its density is 6.8 g $cm^{-3}$. Calculate the number of atoms present in 200 g of the element?

1 Answer

$2.4\times 10^{24}$
Hence (A) is the correct answer.
answered Jun 2, 2014 by sreemathi.v

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