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An element has a body centred cubic (bcc) structure with a cell edge of 288 pm. The density of the element is 7.2 g $cm^{−3}$. How many atoms are present in 208 g of the element?

1 Answer

$12.08\times 10^{23}$
Hence (A) is the correct answer.
answered Jun 2, 2014 by sreemathi.v

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