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In the cubic solid of $CsCl (d = 3.97 g cm^{-3}$) the eight corners are occupied by Cl- with a $Cs^+$ at the center and vice versa. Calculate the distance between the neighbouring $Cs^+$ and $Cl^-$ ions. What is the radius ratio of the two ions?

1 Answer

$4.13\times 10^{-8}cm,0.73A^{\large\circ}$
Hence (A) is the correct answer.
answered Jun 2, 2014 by sreemathi.v

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