logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Solid State
0 votes

A crystal of Lead (II) sulphide has NaCl structure. In this crystal the shortest distance between the $Pb^{2+}$ ion and $S^{2−}$ ion is 297 pm. What is the length of the edge of the unit cell in lead sulphide? Also calculate the unit cell volume.

Can you answer this question?
 
 

1 Answer

0 votes
$a=5.94\times 10^8cm,V=a^3=2.096\times 10^{-12}cm^3$
Hence (A) is the correct answer.
answered Jun 2, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...