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A point charge causes and electric flux $-3 × 10^{14} N-m^2 /C$ to pass through a spherical Gaussian surface If the radius of the Gaussian surface is double, how much flux would pass through the surface?

1 Answer

Electric flux passing through the surface remains unchanged because it depends only on charge enclosed by the surface and is independent of its size.
answered Jun 2, 2014 by meena.p