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Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Solid State
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A metal of density $7.5 × 10^3 kg m^{–3}$ has an fcc crystal structure with lattice parameter a = 400 pm. Calculate the number of unit cells present in 0.015 kg of the metal.

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$3.125 \times 10^{22 }$
Hence (C) is the correct answer.
answered Jun 3, 2014 by sreemathi.v
 
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