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Calculate the amount of work done in turning electric dipole of dipole movement $3 \times 10^{-8}\; C-m$ from its position of unstable equilibrium to the position of stable equilibrium, in a uniform electric field of intensity $10^3 \;N/C.$

1 Answer

$ -6 \times 10^{-5} \;J$
Hence A is the correct answer.
answered Jun 3, 2014 by meena.p

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