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Obtain by the method of dimensional analysis an expression for the surface tension of a liquid rising in a capillary tube. Assume that the surface tension depends on mass m of the liquid, pressure P of the liquid and radius r of the capillary tube. The constant $ k = \large\frac{1}{2}$.

1 Answer

$\sigma = \large\frac{1}{2}$$m^{\circ}p^1r^1 [ \because k = \large\frac{1}{2}$$ ( given ) ] \: or\: \sigma = \large\frac{pr}{2}$
Hence (A) is the correct answer.
answered Jun 3, 2014 by thanvigandhi_1

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