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Assuming that the escape velocity for a planet depends upon gravitational constant G, radius R of planet and also its density $ \rho $, derive formula for escape velocity from dimensional considerations.

1 Answer

$V_e = kG^{\large\frac{1}{2}}$$R^1 \rho^{\large\frac{1}{2}}$ or $V_e = kR \sqrt{G \rho}$
Hence (C) is the correct answer.
answered Jun 3, 2014 by thanvigandhi_1

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