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The special theory of relativity reveals that the length of an object, moving with a speed close to the speed of light, appears shorter in length in the direction of motion. Prerna writes the relation that shows the extent of contraction of a rod as: $ L = L_0 \bigg( 1- \large\frac{1}{c^2} \bigg)^{\large\frac{1}{2}}$ Where, $c \rightarrow $ Speed of light, $L_0$ = Actual length, $L$ = Apparent length Her sister Pooja tells her that this formula is dimensionally incorrect. To make this relationship dimensionally correct, Prerna should

1 Answer

write $v^2$ in place of 1 in the fraction $ \large\frac{1}{c^2}$
Hence (C) is the correct answer.
answered Jun 3, 2014 by thanvigandhi_1

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