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A plastic rod of length $2.2\; m$ and radius $3.6\; mm$ carries a negative charge of $3.8 × 10^{-7}\; C$, spread uniformly over its surface. What is the electric field near the mid-point of the rod, at a point on its surface?

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$-8.6 \times 10^5\;NC^{-1}$
Hence C is the correct answer.
answered Jun 3, 2014 by