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# The electric field intensity vector in a region of space is given by $\overrightarrow{E} = 4 \hat i +3 \hat j +2 \hat k N c^{-1}$. The electric flux through a surface area of $50 m^2$ in $x−y$ plane is

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The electric flux through a surface area of $50 m^2$ in $x−y$ plane is $100 \;N m^2 C^{−1 }$
Hence A is the correct answer.
answered Jun 3, 2014 by

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