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5.35 g of a salt ACl (of weak base AOH) is dissolved in 250 ml of solution. The pH of the resultant solution was found to be 4.827. Find the ionic radius of $A^+$ and $Cl^–$ if ACl forms CsCl type crystal having $2.2 g/cm^3$. Given Kd(AOH) = $1.8 × 10^{–5}$ $\large\frac{r^+}{r^-}$$ = 0.732$ for this cell unit

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Hence (C) is the correct answer.
answered Jun 4, 2014 by sreemathi.v

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