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# KCl Crystallizes in the same type of lattice as does NaCl. Given that, $\large\frac{r_{Na^+}}{r_{cl^-}}$$=0.5 and \large\frac{r_{Na^+}}{r_{k^+}}$$=0.7$.Calculate:( b) The ratio of density of NaCl to that for KCl.

1.172
Hence (A) is the correct answer.