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A proton is fired towards a positively charged plate located at a distance $x$. As the proton reaches just close to the plate, it stops there. The surface charge density of the plate is $4 \times 10^{−6} C/m^2$. If the proton was fired with the initial kinetic energy of $85\; eV$, then what is the value of distance $x$?

1 Answer

The value of distance $x$ is $1.88 \times 10^{-4} m$
Hence D is the correct answer.
answered Jun 4, 2014 by meena.p

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