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Home  >>  AIMS  >>  Class11  >>  Physics  >>  Units and Measurement
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The percentage error in specific resistance $p = \pi r^2R/ l$, where r = radius of wire = $(0.26 \pm 0.02)$ cm, l = length of wire = $(156.0 \pm 0.1) $ cm, R = resistance of wire = $ (64 \pm 2) $ ohm.

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$ \pm18.6 \%$
Hence (A) is the correct answer.
answered Jun 4, 2014 by thanvigandhi_1
 

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