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The potential energy u of a particle varies with distance x from a fixed origin as $ u = \large\frac{A \sqrt x}{x^2+B}$ where A and B are dimensional constants. The dimensional formula for AB is

1 Answer

$M^1 L^{\large\frac{11}{2}} T^{ – 2}$
Hence (B) is the correct answer.
answered Jun 4, 2014 by thanvigandhi_1

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