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Write the intercept cut off by the plane \( 2x+y-z=5\) on x - axis.

1 Answer

Toolbox:
  • Equation of a plane in intercept form is $\large\frac{x}{a}$$+\large\frac{y}{b}$$+\large\frac{z}{c}$$=1$
  • Where $a,b,c$ are the intercepts cut off by the plane at $x,y$ and $z$ respectively.
Step 1:
The given equation is $2x+y-z=5$
Divide throughout by 5,we get
$\large\frac{x}{\Large\frac{2}{5}}$$+\large\frac{y}{5}$$+\large\frac{z}{-5}$$=1$
Step 2:
Equation of a plane in intercept form is $\large\frac{x}{a}$$+\large\frac{y}{b}$$+\large\frac{z}{c}$$=1$
Where $a,b,c$ are the intercepts cut off by the plane at $x,y$ and $z$ axes respectively.
$a=\large\frac{2}{5}$$,b=5$ and $c=-5$
Thus the intercepts cutoff by the plane are $\large\frac{5}{2}$$,5$ and $-5$
answered Dec 2, 2013 by sreemathi.v
 

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