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Write the value of $ \int \sec\: x (\sec\: x+\tan \: x)dx $

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Toolbox:
  • $\int \sec^2xdx=\tan x+c$.
  • $\int \sec x\tan xdx=\sec x+c$.
$\int \sec x(\sec x+\tan x)dx=\int \sec^2xdx+\sec x\tan x dx$.
$\Rightarrow\tan x+\sec x+c.$
Hence $\int \sec x(\sec x+\tan x)dx=\tan x+\sec x+c.$
answered Dec 2, 2013 by sreemathi.v
 
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