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Home  >>  AIMS  >>  Class12  >>  Physics  >>  Electric Charges and Fields
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A charged particle q is shot towards another charged particle Q which is fixed, with a speed . It approaches Q up to a closest distance r and then returns. If q is shot with speed 2 v, the closest distance of approach would be

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The closest distance of approach would be $\large\frac{r}{4}$
Hence A is the correct answer.
answered Jun 6, 2014 by meena.p
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