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Charge $q_2$ of mass m revolves around a stationary charge $q_1$ in a circular orbit of radius r. The orbital periodic time of $q_2$ would be

1 Answer

The orbital periodic time of $q_2$ would be $\bigg[\large\frac{4 \pi^3 mr^2}{k q_1q_2} \bigg]^{1/2}$
Hence A is the correct answer.
answered Jun 6, 2014 by meena.p
 

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