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Home  >>  CBSE XII  >>  Math  >>  Model Papers
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Write the value of $ \sin\bigg[ \large\frac{\pi}{3}$$-sin^{-1} \bigg( -\large\frac{1}{2} \bigg) \bigg]. $

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  • $\sin\big(\large\frac{\pi}{2}\big)$$=1$
$\sin \bigg[\large\frac{\pi}{3}$$-\sin^{-1}\big(-\large\frac{1}{2}\big)\bigg]$
$\sin^{-1}\big(-\large\frac{1}{2}\big)=-\large\frac{\pi}{6}$
$\therefore \sin\big[\large\frac{\pi}{3}-\big(-\large\frac{\pi}{6}\big)\big]$$=\sin\big[\large\frac{\pi}{3}+\frac{\pi}{6}\big]$
$\Rightarrow \sin\big(\large\frac{3\pi}{6}\big)$
$\Rightarrow \sin\big(\large\frac{\pi}{2}\big)$
$\Rightarrow 1$
answered Dec 2, 2013 by sreemathi.v
 
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