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Home  >>  AIMS  >>  Class12  >>  Physics  >>  Electric Charges and Fields
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Under the action of a given coulombic force the acceleration of an electron is $2.5 \times 10^{22} m/s^2$. Then the magnitude of the acceleration of a proton under the action of same force is nearly

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$(C) \; 1.5 \times 10^{19} m/s^2$
Hence C is the correct answer.
answered Jun 6, 2014 by meena.p

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