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Positive and negative point charges of equal magnitude are kept at$\bigg(0,0,\frac{a}{2} \bigg)$ and $\bigg(0,0,\frac{-a}{2}\bigg)$ respectively. The work done by the electric field when another positive point charge is moved from (–a, 0,0) to (0,a,0) is

1 Answer

(C) zero
Hence C is the correct answer.
answered Jun 6, 2014 by meena.p

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