Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Liquid Solutions
0 votes

One litre of sea water weighs 1030 g and contains about $6 \times 10^{–3}g$ of dissolved $O_2$. What will be the concentration of dissolved oxygen in ppm?

Can you answer this question?

1 Answer

0 votes
Mass of $O_2$ in mg = $6 \times 10^{–3}g \times 10^3 mg/g = 6mg$
ppm of O2 in 1030 g sea water =$\large\frac{Mass \;of \;O_2\; in\; mg}{mass\;of\;sea\;water\;in\;kg}=\frac{6}{(1030/1000)kg}$
$\Rightarrow \large\frac{6\times 1000}{1030}$$=5.8ppm$
Hence (A) is the correct answer.
answered Jun 6, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App